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The current in the given circuit is increasing with a rate `a=4 amp//s`. The charge on the capacitor at an instant when the current in the circuit is 2 amp will be:
image
A. `4 muC`
B. `5 muC`
C. `6 muC`
D. none of these

1 Answer

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Best answer
Correct Answer - C
Applying loop law
`4-IR-(LdI)/(dt)-q/C=0`
`4-2xx1-1xx4-q/3=0`
image
`q=-6muC`

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