Question

A variable magnetic field creates a constant emf `E` in a conductor `ABCDA`. The resistances of portion `ABC, CDA` and `AMC` are `R_(1), R_(2)` and `R_(3)` repectively. What current will be shown by meter `M`? The magnetic field is concentrated near the axis of the circular conductor.

Answer 1

Correct Answer - `(ER_(1))/(R_(1)R_(2)+R_(2)R_(3)+R_(3)R_(1))`

`I=E/(R_(2)+(R_(1)R_(2))/(R_(1)+R_(3)))=(E(R_(1)+R_(3)))/(R_(1)R_(2)+R_(2)R_(3)+R_(1)R_(3))`
`I_(m)=R_(1)/((R_(1)+R_(3)))I=(ER_(1))/(R_(1)R_(2)+R_(2)R_(3)+R_(1)R_(3))`