Question

In a transformer, number of turns in the primary coil are 140 and that in the secondry coil are 280. If current i primary ciol is 4A, then that in the secondary coil is
A. `4A`
B. `2A`
C. `6A`
D. `10A`

Answer 1

Correct Answer - 2
Given: `i_(p)=4 A, N_(p)=140`,
`N_(s)=280`
From the formula
`i_(p)/i_(s)=N_(s)/N_(p)`
or `4/i_(s)=280/140`
So, `i_(s)=2A`