Question

A concave mirror of focal length`20cm`is cut into two parts from the middle and the two parts are moved perpendicularly bya distanc e`1cm`from the previous principal axis`AB`.find the distance between the images fromed by the two parts?

Answer 1

Correct Answer - `2cm`

For `m_(1)=(h_(I))/(h_(0))=-(v)/(u)=(f)/(f-u)`
`(h_(I))/(h_(0))=(f)/(f-u)rArr(h_(I))/(h_(0))=(-20)/(-20-(-10))rArr(h_(1))/(-1)=2rArrh_(1)=-2cm`
` v=-((h_(1))/(h_(o)))xxurArrv=-((-2)/(-1))xx-10rArrv=+20cm`