Correct Answer - B
Assertion : `Mn^(3+) = [Ar]^(18) 3d^(4)`, so `n = 4 , Cr^(3+) = [Ar]^(18) 3d^(3)`, so `n = 3 , V^(3+) = [Ar]^(18) 3 d^(2)` , so `n = 2, Ti^(+3) = [Ar]^(18) 3d^(1)`, so `n = 1`.
Reason : `Cr^(3+)` is most stable accroding to `CFSE` (half-filled t2g) configuration gives higher `CFSE` value `3 xx 0.4 = 1.2 Delta p` in octahedral spliting in presenece of ligands.