Question

A charge `q = + 1 muC` is held at 0 between two points A and B such that `AO = 2m and BO = 1m`, Fig . Calculate the value of potential differences `(V_(A) - V_(B))`. What will be the value of potential differences `(V_(A) - V_(B))` if position of B is charged as shown in Fig ?

Answer 1

Here, `q = +1 muC = 10^(-6)C`,
`AO = 2m, BO = 1m`
As shown in Fig .
`V_(A) - V_(B) = (q)/(4pi in_(0)) [(1)/(AO) - (1)/(BO)]`
`= 9xx10^(9)xx10^(-6) [(1)/(2) - 1] = -4500 V`
If position of B is changed as shown in Fig., value of p.d `(V_(A) - V_(B))` shall remain the same. This is because electric potenitial is a scalar quantity and its value does not change with change in orientation of the charges.