Question

A test charge `q_(0)` is moved without acceleration from A to C over the path ABC as shown in Fig.
Calcualate potential difference beetween A and C.

Answer 1

As is clear from Fig. `vec(AB) + vec(BC) = vec(AC)`
As `E = - (dV)/(dr) = (-(V_(C) - V_(A)))/(d) = (V_(A) - V_(C))/(d)`
`:. V_(A) - V_(C) =E.d.`