Question

Two capacitors of capacitances `3 muF and 6 muF`, are charged to potentials 2V and 5V respectively. These two charged capacitors are connected in series. Find the potential across each of the two capacitors now.

Answer 1

Total charge on two capacitors
`= C_(1) V_(1) + C_(2) V_(2)`
`(3xx2+6xx5) = 36 muC`
In series combitions charge is conserved
Potential on `3 muF` capacitor `= (36 muC)/(3 muF) = 12V`
Potential on `6 muF` capacitor `= (36 muC)/(6 muF) = 6V`