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Oxidation state of `Fe` in `K_3[Fe(CN)_6]` is
A. (a) `2`
B. (b) `3`
C. (c) `0`
D. (d) None of these

1 Answer

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Best answer
Correct Answer - B
`3xx(+1)+x+6xx(-1)=0` or `x=6-3+3` Oxidation state of `Fe=+3`.

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