Question

`[Cr(H_2 O)_6]Cl_3` (at no. of Cr = 24) has a magnetic moment of `3.83 B.M`. The correct distribution of `3d` electrons the chromium of the complex.
A. (a) `3dxy^1`, `3dyz^1`, `3dz^2`
B. (b) `3d^1xy`, `3d^1yz`, `3d^1zx`
C. (c) `3d_((x^2-y^2)^1), 3d^1z^2, 3d^1xz`
D. (d) `3dxy^1`, `3d^1x^2-y^2`, `3d^1y^2`

Answer 1

Correct Answer - B
`3.83=sqrt(n(n+2))` so, `n=3`
So, these are three unpaired `e^(-)s`. Based on crystal field splitting the orbital of `t_(29)` set have one `e^(-)` each.