Question

Considering `H_2O` as a weak field ligand, the number of unpaired electrons in `[Mn(H_2O)_6]^(2+)` will be (At. no. of `Mn=25`)
A. (a) `3`
B. (b) `2`
C. (c) `5`
D. (d) `4`

Answer 1

Correct Answer - C
`._(25)Mn: 3d^5, 4s^2`
`Mn^(2+): 3d^5`, i.e., 5 unpaired electrons because `H_2O` is weak field ligand and does not force to pairing.