Question

An electric dipole is placed at an angle of `60^(@)` with an electric field of magnitude `4xx10^(5) NC^(-1)`, It experiencs a torque of `8 sqrt(3) Nm`. If length of dipole is 2 cm, determine the magnitude of either charge of the dipole.

Answer 1

Correct Answer - `2xx10^(-3)C`
`tau = p E sin theta = q (2a) E sin theta`
`q = (tau)/(q (2a) E sin theta) = (8 sqrt(3))/(0.02xx4xx10^(5) xx sin 60^(@))`
`= 2xx10^(-3)C`