Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
+1 vote
106 views
in Physics by (98.2k points)
closed by
Three identical spheres, each having a charge q and radius R. are kept in such a way that each touches the other two. The magnitude of the electric force on any sphere due to the other two is
A. `(1)/(4pi in_(0)) ((q)/(R ))^(2)`
B. `(1)/(4pi in_(0)) (3)/(4) ((q)/(R ))^(2)`
C. `(1)/(4pi in_(0)) (sqrt(3))/(4) ((q)/(R ))^(2)`
D. `(1)/(4pi in_(0)) (3)/(2) ((q)/(R ))^(2)`

1 Answer

+1 vote
by (97.8k points)
selected by
 
Best answer
Correct Answer - C
Force one sphere `C` due to `A, F_(AC)` = Force on sphere
`C` due to `B, F_(BC) =(1)/(4pi in_(0)) (q^(2))/((2R)^(2))`
image
Now `F_(AC)` and `F_(BC)` are inclined at `60^(@)` to each other, therefore resultant force on `C` is
`F_(R) = sqrt(F_(AC)^(2) + F_(BC)^(2) + 2 F_(AC) F_(BC) cos 60^(@))`
`= sqrt(F^(2) + F^(2) + 2F^(2) cos 60^(@))`
`= sqrt(3) F` [Taking `F_(AC) = F_(BC) = F`]
`= (1)/(4pi in_(0)) (sqrt(3))/(4) ((q)/(R))^(2)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...