Correct Answer - A
As is clear from Fig, initial potential energy of the system
`U_(1) = (10^(2))/(4pi in_(0)) [(q_(1) q_(2))/(30) + (q_(1) q_(3))/(40) + (q_(2) q_(3))/(50)]`
Find potentail energy of the system `U_(2) = (10^(2))/(4 pi in_(0)) [ (q_(1) q_(3))/(40) + (q_(1) q_(2))/(30) + (q_(2) q_(3))/(10)]`
Change in potentail energy
`U_(2) - U_(1) = (10^(2))/(4 pi in_(0)) [ (q_(2) q_(3))/(10) - (q_(2) q_(3))/(50)]`
`U_(2) - U_(1) = (10^(2))/(4 pi in_(0)) (q_(2) q_(3))/(50) xx4 = (8 q_(2) q_(3))/(4pi in_(0))`
`:. k = 8 q_(2)`