Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
64 views
in Chemistry by (91.1k points)
closed by
The compound that will react most readily with `NaOH` to from methanol is
A. `(CH_(3))_(4)N^(+)I^(-)`
B. `CH_(3)OCH_(3)`
C. `(CH_(3))_(3)S^(+)I^(-)`
D. `(CH_(3))_(3)CC1`

1 Answer

0 votes
by (90.3k points)
selected by
 
Best answer
Correct Answer - A
Compound `(CH_(3))_(4)N^(+)I^(-)` is most reactuve due to `(i)` bettery leaving group `I^(-)` and `(ii)` due to the fact that the Methyl group, with positive `N`, is not more electron deficient.
Hence this group is more reactive towards nucleophile,
image

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...