(a)Potential difference between A and B = 6 V. As potential at B = 0,
So the potential at A = 6V
Since the potential difference between points A and C = 4 V. Therefore, potential at C = 6 - 4 = 2 V
(b) Let the potential at point D be the same as at C. Then potential difference between A and D = potential between A and C = 4V.
The length AD of potentimeter wire
`=100/6 xx 4 = 66.7 cm`
(c ) IF points C and D are connceted by a wire, then current through this wire is zero because potential at C is equal to potential at D.
(d) If 4V battery is replaced by 7.5 V battery, then potential difference between A and C = 7.5 V. As point A is at 6V, the point C will be at - 1.5 V. Since the voltage of the battery to be balanced on potentiometer wire is more than fall of potential across the potentiometer wire, no balance point like D would exist on wire.