Correct Answer - 288
`32H_(2)O+S_(8)to8H_(2)SO_(4)+48H^(o+)+48e^(Theta)`
`underline([e^(Theta)+H^(o+)+HNO_(3)toNO_(2)+H_(2)O]xx48)`
`underset(1 mol)(S_(8))+48HNO_(3)to8H_(2)SO_(4)+48NO_(2)+underset(16" mol")(16H_(2)O)`
`implies` mass of `H_(2)O` formed `=(16)(18)g=288g`
