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An enantiomerically pure acid is treated with racemic mixture of an alcohol having one chiral carbon. The ester formed will be :
A. Optically active mixture
B. Pure enantiomer
C. Meso compound
D. Recemic mixture

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Correct Answer - A
The poptaically active acid will react with `d and l` forms of alcohol present in the recemic mixture at different rates to form two diastereomers in unequal amount leading to optical activity of the product.

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