Correct Answer - (a)`7.5 V, 1.5A`(b) - 1.5V, 7.5A`
In circuit (a)
Here two cell the connected in opposition so .Effective emf of the circuit `epsilon = 9 - 6 = 3V`, total resistance of circuit `R = 1+ 1 = 2 Omega` current recorded by ideal ammeter
`I =- (epsilon )/(R ) = (3)/(2) = 1.5 A`
As the current `I` flow from position to negative terminal inside the cell of `6 V`, i.e , the cell `6V` is being charged so terminal potential difference of the cell is
`V = epsilon + I r = 6 + 1.5 xx 1= 7.5 V`
Reading of voltmeter `= 7.5 V`
In circuit (b)
Effective emf of the circuit `epsilon = 9 - 6 = 15V` total resistance of circuit `R = 1+ 1 = 2 Omega` current recorded by ideal ammeter
`I = (epsilon )/(R ) = (15)/(2) = 7.5 A`
As the current `I` flow from `-v` to terminal in `+v` terminal inside the cell of `6 V,` i.e , the cell `6V` is being charged so terminal potential difference of the cell is
`V = epsilon - Ir = 6 7.5 xx 1= -1.5 V`
Reading of voltmeter `= -1.5 V`
Reading of ammeter `= 7.5 A`
