(a) There is a radial outward conduction current. Let `Q` be the instantaneous charge on the inner sphere, then,
`j xx 4 pi r^(2) = - (dQ)/(dt)` or, `vec(j) = - (1)/(4pi r^(2)) (d Q)/(dt) hat(r)`
On the other hand `vec(j_(d)) = (del vec(D))/(del t) = (d)/(dt) ((Q)/(4pi r^(2)) hat(r)) = -vec(j)`
(b) At the given moment, `vec(E) = (q)/(4pi epsilon_(0) epsilon r^(2)) hat(r)`
Then, `vec(j_(d)) = (q)/(4pi epsilon_(0) epsilon rho r^(2)) hat(r)`
and `oint vec(j_(a)).d vec(S) = - (q)/(4pi epsilon_(0) epsilon rho) rho (d S cos theta)/(r^(2)) = - (q)/(epsilon epsilon_(0) rho)`
The surface intergal must be `-ve` because `vec(j_(d))` being opposite of `vec(j)`, is inward.