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The total power content of an `AM` wave is `1500 W`. For `100%` modulation, the power transmitted by the carrier is
A. `500W`
B. `700W`
C. `750W`
D. `1000W`

1 Answer

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Correct Answer - D
(`4`) `(P_(t))/(P_(c))=1+(m^(2))/(2)` or `P_(c)=P_(t)[(2)/(2+m^(2))]`
`P_(c)=1500[(2)/(2+1)] :. M=100%=1=1000W`

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