The uniform charge −Q will be induced on inner surface of the shell and +Q will be induced on outer surface. This is follows from conservation of charge and no static charges resides in the interior of a metal in electrical equilibrium.
Using Gauss's law the field at P1:
\(E.4\pi r^2_1 = \frac{Q_{en}}{\varepsilon_0}\) where Qen = +Q, charge inside gaussian surface of radius r1.
Thus, \(E = \frac{Q}{4 \pi \varepsilon_0 r_1^2}\)
