Question

The circular scale of a screw gauge has `200` divisions. When it is given `4` complete rotations, it moves through `2mm`. The least count of the screw gauge is
A. `0.25xx10^(-2)cm`
B. `0.25xx10^(-3)cm`
C. `0.001cm`
D. `0.001mm`

Answer 1

Correct Answer - B
`LC=("pitch of the screw")/("number of circular scale divisions")`
`=(2)/(4(200))=0.25xx10^(-3)cm`