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To use the milliammeter of the previous question as a voltmeter of range `10 V`, a resistance `R` is placed in series with it. The value of `R` is
A. `9 Omega`
B. `99 Omega`
C. `999 Omega`
D. `1000 Omega`

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Correct Answer - C
`V = i_g (R + G)`
`10 = 10 xx 10^-3(R + 0.9) rArr R = 999 Omega`.

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