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In the previous question, maximum permissible error is resitivity and resistance measurement will be
A. `2.14%`, `1.5%`
B. `1.5%`, `2.45%`
C. `2.41%`, `1.1%`
D. `2.45%`, `1.5%`

1 Answer

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Best answer
Correct Answer - C
`((dR)/(R))_(max)=(Deltai)/(i)+(Deltav)/(v)=`
`(0.1)/(10.0)+(0.1)/(100.0)=1.1% ((dR)/(R))_(max)=2.41%`

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