Correct Answer - C
`F_(m) = (mu_(0))/(4pi)(e.e.v.v)/(r^(2)) = (mu_(0)e^(2)v^(2))/(4pi r^(2))`
`F_(e) = (1)/(4pi in_(0)).(e.e)/(r^(2))`
`(F_(e))/(F_(m)) = (1)/(mu_(0) in_(0)v^(2)) = (c^(2))/(v^(2))`
Since `c gt gt v, F_(e) gt gt F_(m)`
`F_(m) = (mu_(0)i.i)/(2pi d) = (mu_(0)i^(2))/(2 pi d)`