Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
68 views
in Physics by (87.2k points)
closed by
A point `P` lies on the axis of a flat coil carrying a current. The magnetic moment of the coil is `mu`. The distance of `P` from the coil is `d`, which is large compared to the radius of the coil. The magnetic field at `P` has magnitude
A. `(mu_(0))/(2pi)((mu)/(d^(3)))`
B. `(mu_(0))/(4pi)((mu)/(d^(3)))`
C. `(mu_(0))/(2pi)((mu)/(d^(2)))`
D. `(mu_(0))/(4pi)((mu)/(d^(2)))`

1 Answer

0 votes
by (84.6k points)
selected by
 
Best answer
Correct Answer - A
image
`B = (mu_(0)Nir^(2))/(2(r^(2) + d^(2))^(3//2)) = ((mu_(0) Nipi r^(2)))/(2pid^(3)(r^(2)//d^(2) + 1)^(3//2))`
`= (mu_(0)mu)/(2pi d^(3))`
Since `N i pi r^(2) = NiA = ,mu, r lt lt d, (r^(2))/(d^(2))` is negligible.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...