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A rectangular loop of sides `20 cm` and `10 cm` carries a current of `5.0 A`. A uniform magnetic field of magnitude `2 T` exists parallel to the longer side of the loop. The torque acting on the loop is
A. `0.2 Nm`
B. `0.3 Nm`
C. `2 Nm`
D. `3 Nm`

1 Answer

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Best answer
Correct Answer - A
`tau = MB sin theta = iAB sin 90^(@) = i(l xx b)B`
`= 5(20 xx 10 xx 10^(-4)) xx 2`
`= 0.2 Nm`

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