Correct Answer - D
Since no `e^(-)` is seen in the given reaction, it can be regarded as a cell reaction, whose standard EMF will be given as follows :
`E_("cell")^(@) = E_(R)^(@)-E_(L)^(@)`
Electrode having the higher reduction potential acts as cathode. Thus, `E_("cell")^(@) = (0.771 V)-(-0.441 V)`
`= 1.212 V`