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`n` idential capacitors each of capacitance `C` when connected in series give equivalent capacitance `1.2muF` and when connect in parallel give `120muF`. Then `n` and `C` are
A. `5` and `10muF`
B. `10` and `12muF`
C. `10` and `6muF`
D. `12` and `10muF`

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Correct Answer - B
`(C)/(n)=1.2` ….(i)
`nC=120` …(ii)
`(i)xx(ii)impliesC^(2)=144impliesC=12muF`
`n=10,C=12muF`

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