Question

In the following circuit, the resultant capacitance between `A` and `B` is `1muF`. Then value of `C` is

A. `(32)/(11)muF`
B. `(11)/(32)muF`
C. `(23)/(32)muF`
D. `(32)/(23)muF`

Answer 1

Correct Answer - D
`C_(eq)=(Cxx(32)/(9))/(C+(32)/(9))`
`1=(32C//9)/((9C+32)//9)=(32C)/(9C+32)`
`9C+32=32Cimplies23C=32` ltbRgt `C=(32)/(23)muF`