Question

Two capacitors of capacitances `3muF` and `6muF` are charged to a potential of `12V` each. They are now connected to each other, with the positive plate of each joined to the nagative plate of the other.
(A) the common potential will be `12V`
(B) the loss in energy will be `576muJ`
(c) the common potential will be `4V`
(D) the loss in energy will be `144 muJ`
A. `A,B`
B. `A,D`
C. `B,C`
D. `C,D`

Answer 1

Correct Answer - C
Common potential `V=(6xx12-3xx12)/(6+3)=4V`
Loss in energy `DeltaU=(1)/(2).(3xx6)/(3+6)(12+12)^(2)xx10^(-6)J`
`=576muJ`