At ,maximum separation velocity of point mass is zero.From work energy theorem
`W_("spring")+W_("field")=0`
` qEx_(0)-(1)/(2)kx_(0)^(2)(x_(0)` maximum elongation)
`rArr x_(0)=(2qE)/(K),:.`separation =`L+(2qE)/(k)`
(b) At equilateral position `EqEq=kxrArr x=(qE)/(k)`
`rArr"separation"=L+(qE)/(k)`
c )`U=(1)/(2)kx^(2)=(1)/(2)k((qE)/(k))^(2)=(q^(2)E^(2))/(2k)`