Correct Answer - 3
According to right hand thumb rule, the magnetic field due to current `I_(1)` in the wire at point `O_(2)` is along `y-` axis.
We know, magnetic force, `vec(F)_(m)=Ivec(l)xxvec(B)`
Here, `vec(B)=-Bhat(y) and hat(l)=lhat(y)`
`:. vec(F)_(m)=-IlB(hat(y)xxhat(y))=vec(0)`