Correct Answer - C
`r=(sqrt(3)l)/(2)`
`B=6[(mu_(0))/(4pi)(i)/(r)(sin 60^(@)+sin60^(@))]`
`-6[(mu_(0))/(4pi).(i)/(r)(sin30^(@)+sin30^(@))]`
`=6xx(mu_(0))/(4pi).(i)/(r)(sqrt(3)-1)`
`=6xx(mu_(0))/(4pi).(i)/(((sqrt(3)l)/(2)))(sqrt(3)-1)`
`=(3-sqrt(3))[(mu_(0)i)/(pi l)]`