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A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-parti

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A proton and an alpha - particle are accelerated through same potential difference. Then, the ratio of de-Broglie wavelength of proton and alpha-particle is
A. `1:2sqrt2`
B. `2:1`
C. `2sqrt2:1`
D. `4:1`
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Correct Answer - C
`lambda_(p)/lambda_(alpha)=sqrt(q_(alpha)/q_(p)xxm_(alpha)/m_(p)`
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