Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
274 views
in Physics by (87.2k points)
closed by
Switches `S_(1), S_(2)` remain open and switch `S_(3)` remains closed for long time such that capacitor becomes fully charged and current in inductor coil becomes maximum, Now switches `S_(1), S_(2)` are simultaneously closed and`S_(3)` in simultaneously opened at `t=0`
Assume that battery and inductor coil are ideal
image
Find time `t gt 0`, when energy store in inductor would have minimum for the first time ?
A. `(pi)/(4) xx 10^(-4) s`
B. `(pi)/(4) xx 10^(-4) s`
C. `(3pi)/(4) xx 10^(-4) s`
D. `pi xx 10^(-4) s`

1 Answer

0 votes
by (84.6k points)
selected by
 
Best answer
Correct Answer - C
When energy store in inductor is minimum at that time energy strore in capacitor is maximum `|q_(max)|` first time when
`10^(4)t+(3pi)/(4) = (3pi)/(2) rArr t = (3 pi)/(4) xx 10^(-4)`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...