`r_(eq)=1+2+3+4 = 10Omega`
`i=10/(R_(eq)) = (10)/(10)=1Omega`
`V_(A)-ixx1-ixx2=V_(C)implies V_(A)-V_(C)=3i=3xx1=3V`
Charge on `5Uf : Q_(1) = 5 (V_(A)-V_(C)) = 5xx3 = 15mu C`
`V_(B)-ixx2-ixx3=V_(D)implies V_(B)-V_(D)=5i=5xx1=5V`
Charge on `3muF: Q_(2)=3(V_B-V_D)=3xx5=15muC`.