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Three equal resistor connected in series across a source of enf together dissipate `10 Watt`. If the same resistors aer connected in parallel across the same emf, then the power dissipated will be
A. 10 Watt
B. 30Watt
C. `10//3 Watt`
D. `90Watt`

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Correct Answer - D
`P_(1) = 10 = (V^2)/(3R) , P_(2) = (V^2)/(R//3)`
`(P_2)/(P_1) = 9 implies P_(2) = 9P_(1) = 90 W`.

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