Correct Answer - C
`phi = BA cos omega t`
`e = - (d phi)/(dt) = BA omega sin omega t`
`i_("rms") = (V_("rms"))/(Z) = (BA omega // sqrt(2))/(sqrt((omega L - (1)/(omega C))^(2) + R^(2)))`
`= (0.1 xx 10^(-3) xx 63)/(sqrt(2 { (63 x 0.1 - (1)/(63 xx 0.01))^(2) + (10)^(2)}))`
`= 4.0 xx 10^(-5) A`