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If `E=at+bt^(2)`, what is the neutral temperature

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If `E=at+bt^(2)`, what is the neutral temperature
A. `-(a)/(2b)`
B. `+(a)/(2b)`
C. `-(a)/(b)`
D. `+(a)/(b)`
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Correct Answer - A
`E = a t + bt^(2)`
For netual temperature
`(dE)/(dt) = a.1+b . 2t = 0`
`t = -(a)/(2b)`.
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