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A silicon specimen is made into a `P`-type semiconductor by dopping, on an average, one helium atoms per `5xx10^(7)` silicon atoms. If the number density of atoms in the silicon specimen is `5xx10^(28) at om//m^(3)` then the number of acceptor atoms in silicon per cubic centimeter will be
A. `2.5xx10^(30)atoms//cm^(3)`
B. `1.0xx10^(13)atoms//cm^(3)`
C. `1.0xx10^(15)atoms//cm^(3)`
D. `2.5xx10^(36)atoms//cm^(3)`

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Correct Answer - C
Number of indium atoms=`(5xx10^(28))/(5xx10^(10^(7)))=10^(21)//m^(3)=10^(15)//cm^(3)`

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