Question

The resonce frequency of the tank cuircuit of an oscillator when `L=(1)/(pi^(2))mH` and `C=0.04 muF` are connected in parellel is
A. `250kHz`
B. `25kHz`
C. `2.5 kHz`
D. `25 MHz`

Answer 1

Correct Answer - B
`f=(1)/(2pi)sqrt((1)/(LC))`
`=(1)/(2pi)sqrt((1)/(10/(pi^(2))xx10^(-3)xx0.04xx10^(-6)))=(1)/(2xx2xx10^(-5))`
`=0.25xx10^(5)=25kHz`