Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.3k views
in Physics by (88.6k points)
closed by
The radius of the oxygen nucleus `._(8)^(16)O` is `2.8 xx 10^(-15)m`. Find the radius of lead nucleus `._(82)^(205)Pb`.

1 Answer

0 votes
by (90.6k points)
selected by
 
Best answer
`R_(0) = 2.8 xx 10^(-15)m, A_(0) = 16, A_(Pb) = 205 R prop A^(1//3)`
`(R_(0))/(R_(Pb)) = ((A_(0))/(A_(Pb)))^(1//3) = (2.8 xx 10^(-15))/(R_(Pb)) = ((16)/(205))^(1//3)`
`R_(Pb) = 6.55 xx 10^(-15)m`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...