Question

`1 kg` of iron (specific heat `120 Cal Kg^(-1) C^(-1)`) is heated by `1000^(@)C`. The increases in its mass is
A. zero
B. `5.6xx10^(-8) Kg`
C. `5.6xx10^(-16)Kg`
D. `5.6xx10^(-12) Kg`

Answer 1

Correct Answer - D
`Delta mc^(2)=J(MS Delta t)`

Answer 2

Correct option is D. \(5.6 \times 10^{-12}kg\)

\(\Delta mc^2 = ms\Delta T\)

\(\Delta m = \frac {1\times 120 \times 4.2 \times 1000}{(3\times 10^8)^2}\)

\(\Delta m = \frac {504\times10^3}{9\times10^{16}}\)

\(\Delta m= 56 \times 10^{-13}\)

\(\Delta m= 5.6 \times 10^{-12}kg\)