Question

`50%` of a radio active substance decays in `5` hours. The time required for the `87.5%` decays is
A. `10` hours
B. `15` hours
C. `12.5` hours
D. `17.5` hours

Answer 1

Correct Answer - B
`W=(W_(0))/(2^(n)) n=(t)/(t_((1)/(2))), t_(1//2)= 5 hrs`