Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
69 views
in Physics by (88.6k points)
closed by
The count rate from `100cm^(3)` of a radioactive liquid is `c`. Some of this liquid is now discarded. The count rate of the remaining liquid is found to be `c//10` after three half-lives. The volume of the remaining liquid, in `cm^(3)`, is
A. `20`
B. `40`
C. `60`
D. `80`

1 Answer

0 votes
by (90.6k points)
selected by
 
Best answer
Correct Answer - C
Initial count rate of `1 cm^(3)` of liquid `=(C)/(100)`
After 3 half-lives, count rate of the liquid `=(1)/(8)xx(C)/(100)`
Let V be the volume of the remaining liquid. The CR of this liquid `=(VC)/(800), (C)/(10)=(VC)/(800)rArrV=80`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...