Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
127 views
in Physics by (90.6k points)
closed by
A full wave rectifier uses two diodes with a load resistance of `100 Omega`. Each diode is having negligible forward resistance. Find the efficiency of this wave rectifier.

1 Answer

0 votes
by (88.6k points)
selected by
 
Best answer
Forward resistance of the diode `r_(f) = 0` ,
Load resistance, `R_(L) = 100 Omega , eta = ?`
efficiency of full wave rectifier
`= (0.812 xx 100)/(100) = 0.812`
The percentage efficiency of the full wave rectifier `= 81.2 %`.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...