Correct Answer - D
`n_(e)=n_(h)=n_(i)`
`:. sigma = n_(i)e(mu_(e)+mu_(h)) = 1.6 xx 1.6 xx 0.6 xx10^(-13)`
Current produced in germanium plate.
`I=JA = sigma E.A = sigma((V)/(d))A`
Here generated in the plate, `H = V xx I xx t`
`= 5xx1.28 xx10^(-13)xx100 =6.4 xx10^(-11)` joule.