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For a transistor `x=(1)/(alpha)&y=(1)/(beta)` where `alpha & beta` are current gains in common base and common emitter configuration. Then
A. `x+y =1`
B. `x -y =1`
C. `2x =1 - y`
D. `x+y =0`

1 Answer

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Best answer
Correct Answer - B
`alpha -(Delta I_(c))/(Delta I_(e)), beta =(Delta I_(c))/(Delta I_(b))`.

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